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CGP EDU Academic Team
Published on: September 12, 2026
An ideal heat engine exhausting heat at 77^\circ C is to have a 30% efficiency. It must take heat at
Text Solution
Verified by ExpertsThe correct answer is:
B
$\eta = 1 - \frac{T_2}{T_1} \Rightarrow \frac{30}{100} = 1 - \frac{350}{T_1}$ $\Rightarrow \frac{350}{T_1} = 1 - \frac{50}{100} = \frac{70}{100} = \frac{7}{10} \Rightarrow T_1 = 500K = 227^\circ C$
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